The height of a cylinder is three times the diameter of the base. The surface area of the cylinder is 126pi sq ft. What is the radius of the base?
Surface Area of Right Circular Cylinder is ...? In terms of Height and Radius.
Well. I know the formula is S.A. = L.A.+2B
Where B is the area of the base.
Very good. Now expand both "L.A." and "B" to be in terms of the Radius and Height.
Would that be 2pi r h + 2pi r squared?
Super. One more thing. In the problem statement, we are told h = 3d = 2(3r) = 6r. Do you see this?
Yes
Wait I think I get it!
Okay, we're ready to solve. Write the rest of the problem statement.
See how sly you are?! Now, solve directly for 'r'. Perfect!
I don't know if I'm doing my math right. I get something not in my choices, but it's closest to 3 ft. So that's what I put. Thank you so much!
126pi = 2pi r 6r + 2pi r squared \(2\pi r\cdot 6r + 2\pi r^{2} = 126\pi\) Divide by \(\pi\) \(2 r\cdot 6r + 2r^{2} = 126\) Simplify and divide by 2 \(6r^{2} + r^{2} = 63\) Simplify \(7r^{2} = 63\) Divide by 7 \(r^{2} = 9\) Look's like r = 3 is a good answer. NOT r = -3. That's not a good radius for a real cylinder.
Did I say -3? But thank you again. I did do my math wrong.
No, you did not say "-3". \(r = -3\) IS a solution to \(r^{2} = 9\), but it is not a solution to this problem. Just trying to be thorough.
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