Projectile fired...again
Projectile is fired at intial speed of v0 ft/s at an angle alpha above the horizontal, then its position after t seconds is given by the following parametric equations where x and y are measured in feet. By eliminating the parameter t, it can be shown that the path is a parabola. x= (vocos(alpha)t, y=(vosin(alpha))t-16t^2
Suppose a gun fires a bullet into the air with an initial speed of 2048 ft./s at angle 30 degrees to the horizontals.
a)after how many seconds will the bullet hit the ground? b) how far from the gun will the bullet hit the ground? c) what is the maximum height atttained by the bullet?
@rational :)
Hint : y is 0 when the bullet hits the ground
so i use the second equation and set y to 0?
but first I have to find t. but doing question a
yes set y equal to 0 and find t
y=(vosin(alpha))t-16t^2 0=(vosin(alpha))t-16t^2 plugin the given values and solve t
what does it mean when it says algebraically?
ah, so I do b first? okies.
we're doing a first
a)after how many seconds will the bullet hit the ground? this is about finding time only right
b is about finding the x value
x : horizontal distance y : time
oh oh gotcha.
err so 0=t(2048sin30 - 16t)
divide both sides by t 0=2048sin30-16t
t=2048sin30/16 ?
=64
yes!
bullet hits the ground after 64 seconds
okies and then the answer to b is 21.498 miles?
Yep!
andd c= 10.749 miles?
oh wait, I don't think that's correct. I just divided x by 2 but didn't replug it into the equation
10.749 is the x axis at maximum height but idk the y
forget about x
it took 64 seconds for the entire journey, right ?
yeah. so 32 until max height
yes simply plugin t=32 into the equation for y
the equation where y = 0? or just the right side of the y one
y=0 corresponds to the height when the bullet hits ground
so how is that related to the maximum height ?
ok, so the answer i'm getting is 16384 divided by 5280 to get miles = 3.103
yeah, sorry, that was an uneducated comment :P
looks good!
Fantastic:) thank you so much!
yw
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