Question

\[\sqrt{x}+y=11 and \sqrt{y}+x=7 (solve buy elimination method)\]

Answer 1

Something you can try:
\[\sqrt x+y=11~~\implies~~\sqrt x=11-y~~\implies~~x=(11-y)^2\]
Subtracting this equation from the second gives
\[(\sqrt y+x)-x=7-(11-y)^2\]
This eliminates the \(x\), giving
\[\sqrt y=7-(11-y)^2\]

Answer 2

solve
it must not by putting method

Answer 3

i.e. putting value like 1,2,3

Answer 4

I don't quite understand what you're trying to say. I'm using elimination, as requested by the original question.