Before a nuclear reaction, there is 0.01000 kg of uranium. After the nuclear reaction, there is 0.00950 kg of uranium. How much energy was released? (h = 6.63 × 10^-34 Js)
(Points : 3)
9.00 × 10^16 J

4.50 × 10^13 J

1.50 × 10^5 J

5.00 × 10^-4 J

Question

Before a nuclear reaction, there is 0.01000 kg of uranium. After the nuclear reaction, there is 0.00950 kg of uranium. How much energy was released? (h = 6.63 × 10^-34 Js)
(Points : 3)
       9.00 × 10^16 J

       4.50 × 10^13 J

       1.50 × 10^5 J

       5.00 × 10^-4 J

anonymous · Answer

the energy lost is 0.00050 
by scientific  notation 
d

anonymous · Answer

An electron is an example of which of the following?
(Points : 3)
       antiparticle

       boson

       lepton

       hadron

anonymous · Answer

@leon549

anonymous · Answer

What is the energy of a single photon of red light with a wavelength of 700.0 nm?

Remember that E = hf and Planck's constant is expressed by h = 6.63 × 10^-34 Js = 4.14 × 10^-15 eVs.
(Points : 3)
       4.29 × 10^-20 J

       2.84 × 10^-19 J

       4.98 × 10^-19 J

       2.84 × 10^14 J

anonymous · Answer

lemda = 700nm
lemda = 700 * 10 ^9
lemda = 0.700 *10 ^9

anonymous · Answer

what is lemda?

anonymous · Answer

dude can we talk it middle of the and i cant type

anonymous · Answer

its wavelenght which denoted by a simbol called lemda

anonymous · Answer

oh okay sorry

anonymous · Answer

so in order to find the frequency velocity is very imp

anonymous · Answer

How do i do it

anonymous · Answer

oh wait i Think the answer is B am  I right?

anonymous · Answer

no d

michele_laino · Answer

The released energy, is given by the famous Einstein's relationship, namely:
$$\Large  \begin{gathered}
  E = \Delta m \cdot {c^2} = \left( {0.01 - 0.0095} \right) \times 9 \times {10^{16}} =  \hfill \
   = 4.5 \times {10^{13}}Joules \hfill \ 
\end{gathered} $$