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Mathematics 14 Online
OpenStudy (anonymous):

help pleaseeeeeeeeeeeeeeeee =(

OpenStudy (anonymous):

With What.?

OpenStudy (anonymous):

\[8^{n+1}+8^{n}=36 \] n=

OpenStudy (anonymous):

i got 5/2

OpenStudy (anonymous):

Thats Correct

OpenStudy (anonymous):

it's supposed to be 2/3 tho...

OpenStudy (anonymous):

What did you do?

OpenStudy (anonymous):

i did the exponents like this 3n+3+3n=18

geerky42 (geerky42):

\(8^{n+1}\) is same as \(8\cdot8^n\), right? So you have \(8^{n+1}+8^n = 8\cdot8^{n}+8^n\) Now you can factor \(8^n\) out.

OpenStudy (anonymous):

so was my answer wrong?

geerky42 (geerky42):

yeah n is not 5/2.

OpenStudy (anonymous):

oh so u cant do anything if the base is the same and even if they have exponents if they're addition of subtraction sign? It has to be multiplication to do anything? like adding exponents and such?

OpenStudy (anonymous):

or subtraction not of*

geerky42 (geerky42):

yeah, for you to add exponent and stuffs, you need to have base multiplied; \(a^ba^c = a^{b+c}\) But here, you have \(8^{n+1}+8^n\). You have plus sign instead.

geerky42 (geerky42):

But you can factor it out; you just need exponent to be same

OpenStudy (anonymous):

so whats the next step?

geerky42 (geerky42):

Like I said, \(8^{n+1}\) is same as \(8\cdot8^n\), right? So you have \(8^{n+1}+8^n = 8\cdot8^{n}+8^n\) Now you can factor \(8^n\) out.

geerky42 (geerky42):

Factoring \(8^n\) out will get you \(8^n~(8+1)\)

OpenStudy (anonymous):

wait sorry where does the +1 come from

geerky42 (geerky42):

\(8^{n+1}+8^n = 8\cdot8^{n}+\color{red}{1}\cdot8^n = 8^n~(8+\color{red}{1})\)

geerky42 (geerky42):

\(8^n\) is same as \(1\cdot8^n\)

geerky42 (geerky42):

Does that make sense?

OpenStudy (anonymous):

ummm kind of.....so basically the one is fo the 8^n right?

geerky42 (geerky42):

yeah.

OpenStudy (anonymous):

okay i mean it's kind of weird but maybe i have to keep looking at it for it to sink in

geerky42 (geerky42):

It's just like \(ba+a~~\Rightarrow~~a~(b+1)\)

OpenStudy (anonymous):

oh okay i got it thanks

geerky42 (geerky42):

Ok so you have: \[8^n(8+1)=36\]\[8^n(9)=36\] Divide both sides by 9: \[8^n=4\] Now convert base to 2; \[(2^3)^n = 2^2\]\[2^{3n} = 2^2\] Then since bases are same, we can set exponents equal to each other; \[3n = 2\]\[\boxed{n=\dfrac{2}{3}}\]

geerky42 (geerky42):

Make sense so far?

OpenStudy (anonymous):

yea i was just having trouble with the factoring i got it now thank you so much youre awesome!!!!!

geerky42 (geerky42):

ok you are welcome :)

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