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Mathematics 8 Online
OpenStudy (anonymous):

Grade 8 math (attachment picture) medal for best answer

OpenStudy (anonymous):

OpenStudy (igreen):

We want to get 'p' by itself, so the first step would be to get rid of 9..so what do we do to it?

OpenStudy (anonymous):

@Holt

OpenStudy (igreen):

Btw, nice username \(\large\ddot\smile\)

OpenStudy (anonymous):

thankyou!! :D

OpenStudy (igreen):

We want to do the opposite, And it's being subtracted..so what's the opposite of subtraction?

OpenStudy (anonymous):

add

OpenStudy (anonymous):

addition

OpenStudy (igreen):

Yes, so we add it to both sides. \(\sf \dfrac{p}{5} - 9 + 9 = 14 + 9\) The 9's on the left cancel out, giving us: \(\sf \dfrac{p}{5} = 14 + 9\) Can you add that?

OpenStudy (anonymous):

uh......

OpenStudy (igreen):

\(\sf 14 + 9 = ~ \! ?\)

OpenStudy (anonymous):

23

OpenStudy (igreen):

Yes, so we have: \(\sf \dfrac{p}{5} = 23\) Now do the opposite of dividing 5..multiply.

OpenStudy (calculusxy):

So now you have: \[\frac{ p }{ 5 } = \frac{ 23 }{ 1 }\]

OpenStudy (calculusxy):

That's how I like to think of it -- as a proportion.

OpenStudy (anonymous):

okay so I multiply what numbers again? @holt you have an answer??

OpenStudy (igreen):

Yes, that's a good way to look at it..then you can just cross multiply.

OpenStudy (calculusxy):

5 x 23 = p x 1 (which is in other words p)

OpenStudy (calculusxy):

Rewrite: \[5 \times 23 = p \]

OpenStudy (igreen):

\(\sf \dfrac{p}{5} = 23\) Multiply 5 to both sides just like you did with 9. \(\sf \dfrac{p}{5} \times 5 = 23 \times 5\) The 5's on the right cancel out giving us: \(\sf p = 23 \times 5\)

OpenStudy (igreen):

Just multiply to get your answer.

OpenStudy (anonymous):

aka, A.

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