Grade 8 math (attachment picture) medal for best answer
We want to get 'p' by itself, so the first step would be to get rid of 9..so what do we do to it?
@Holt
Btw, nice username \(\large\ddot\smile\)
thankyou!! :D
We want to do the opposite, And it's being subtracted..so what's the opposite of subtraction?
add
addition
Yes, so we add it to both sides. \(\sf \dfrac{p}{5} - 9 + 9 = 14 + 9\) The 9's on the left cancel out, giving us: \(\sf \dfrac{p}{5} = 14 + 9\) Can you add that?
uh......
\(\sf 14 + 9 = ~ \! ?\)
23
Yes, so we have: \(\sf \dfrac{p}{5} = 23\) Now do the opposite of dividing 5..multiply.
So now you have: \[\frac{ p }{ 5 } = \frac{ 23 }{ 1 }\]
That's how I like to think of it -- as a proportion.
okay so I multiply what numbers again? @holt you have an answer??
Yes, that's a good way to look at it..then you can just cross multiply.
5 x 23 = p x 1 (which is in other words p)
Rewrite: \[5 \times 23 = p \]
\(\sf \dfrac{p}{5} = 23\) Multiply 5 to both sides just like you did with 9. \(\sf \dfrac{p}{5} \times 5 = 23 \times 5\) The 5's on the right cancel out giving us: \(\sf p = 23 \times 5\)
Just multiply to get your answer.
aka, A.
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