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rewrite as an exponential equation ln(x+y)=5
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So, here you need to raise both sides by the exponential e. e^ln(x+y) = e^5. Can you see why we do this?
Not really?? I know when you deal with logs that e is the base of ln
I mean natural logs
@unknownunknown
That's right. So, you can think of ln(x) and e^x as being inverse to each other. \[e^{\ln x} = x \] Likewise, \[\ln e^{x} = x \] These are inverse functions. So, if we want to solve for x that's located in a natural logarithm, we need to apply its inverse function.
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Okay so now what
@unknownunknown
is that all?
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