WILL GIVE MEDAL AND FAN!!!! Debbie and Trisha are looking at the equation the square root of the quantity of 4 times x minus 6 equals square root of x . Debbie says that the solution is extraneous. Trisha says that the solution is non-extraneous. Is Debbie correct? Is Trisha correct? Are they both correct? Justify your response by solving this equation, explaining each step with complete sentences.
ok lets write equation on left hand side square root of the quantity of 4 times x minus 6 first write without squareroot 4 times x= 4x and subtract 6 now .....so is 4x-6 now take square root 4x−6−−−−−√
x=2
they cant be both correct
now you do the rest
Okay I'm super confused o_o
@Flightmaster201
hey write the equation in numeric form u will understand all
I'm just really bad at this. It would help if you like walked me through it and tried to teach me.
ok
4 times x means 4 *x which can be wrtten as 4x
squate root 4 times x minus 6 means sqrt 4x -6
okayy I get that part.
squate root 4 times x minus 6 equalls sqrt x means sqrt 4x -6 = sqrt x this is the equation given in the qustion
get it
now take squares both sides in order to eliminate the sqrt then the equation will become 4x -6 =x 4x = x + 6 4x - x = 6 3x = 6 divide both sides by 3 x = 2 so which is not extranous roots
debbie is wrong which means they both r wrong then trisha is right
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