The current in a solenoid with 21 turns per centimeter is 0.50A . The solenoid has a radius of 1.6cm . A long, straight wire runs along the axis of the solenoid, carrying a current of 13A .

Question

michele_laino · Answer

Please your question is incomplete

anonymous · Answer

oh sorry Find the magnitude of the net magnetic field a radial distance of 0.80cm from the straight wire.

michele_laino · Answer

are you using the CGS system of formulas

michele_laino · Answer

or the MKS system?

michele_laino · Answer

namely the International System IS of unit of measures?

anonymous · Answer

Uh, sorry I don't understand what you mean

anonymous · Answer

I use the international system

anonymous · Answer

sorry

michele_laino · Answer

no worries! :)

michele_laino · Answer

sorry I rewrite my answer

anonymous · Answer

ok

michele_laino · Answer

The magnetic field generated by the solenoid is given by the subsequent formula:
$$\Large  B = \frac{{4\pi n{I_S}}}{c}$$

michele_laino · Answer

where I_S is the current of the solenoid, n is the ration turns per centimeter, and c is the light speed

michele_laino · Answer

ratio*

anonymous · Answer

okay. But I don't understand why I'd need the light speed? Isn't the question asking for the magnetic field in mT?

michele_laino · Answer

ok! So you are using the MKS system

anonymous · Answer

oh. I did not know that. Sorry.

michele_laino · Answer

Using MKS system we have that the magnetic field generated by the solenoid is:
$$\Large B = {\mu _0}n{I_S}$$

michele_laino · Answer

do you recognize that formula?

anonymous · Answer

yes

michele_laino · Answer

where $${\mu _0}$$, ismagnetic permeability of the vacuum

anonymous · Answer

yes.

anonymous · Answer

so would there be another formula which you would add that one to?

michele_laino · Answer

we have to write the magnetic field generated by the wire along the axis of the solenoid

anonymous · Answer

ok

michele_laino · Answer

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