Mathematics
8 Online
OpenStudy (anonymous):
The position of an object at time t is given by s(t) = -2 - 6t. Find the instantaneous velocity at t = 2 by finding the derivative.
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OpenStudy (shamim):
Tell me
ds/dt=?
OpenStudy (anonymous):
Yah
OpenStudy (shamim):
U know
d2/dt=0
OpenStudy (anonymous):
ok
OpenStudy (shamim):
Because derivative of any constant is =0
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OpenStudy (anonymous):
ok
OpenStudy (shamim):
U know 2 is a number. So 2 is a constant. Right?
OpenStudy (anonymous):
yah 2 is a constant and thus the derivative is zero.. so would zero be the answer?
OpenStudy (shamim):
No
OpenStudy (anonymous):
This problem is just confusing me..
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OpenStudy (shamim):
c
d(6t)/dt=6*dt/dt=6*1=6
OpenStudy (anonymous):
I don't understand
OpenStudy (shamim):
ds/dt=d(2)/dt-d(6t)/dt
OpenStudy (shamim):
Nd velocity v=ds/dt
OpenStudy (anonymous):
ok... FLVS doesn't explain derivatives very well sorry
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OpenStudy (shamim):
Plz tell me ur problem specifically
OpenStudy (shamim):
I wanna help u !
OpenStudy (shamim):
Dont u know
Velocity v=ds/dt
OpenStudy (anonymous):
Thanks for the help.. What I think they want is a derivative question that involves solving with the t=2. This is why im confused
OpenStudy (anonymous):
I know that v=ds/dt
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OpenStudy (shamim):
U know v=-6
OpenStudy (shamim):
So v is constant
OpenStudy (shamim):
After time t=2 sec the velocity is v=6
OpenStudy (shamim):
Nd it is negative
OpenStudy (anonymous):
ok... I think I was making it a lot more complicated than it rreally was
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OpenStudy (shamim):
Negative sign indicates direction of velocity
OpenStudy (anonymous):
Ok
OpenStudy (anonymous):
Thanks!
OpenStudy (shamim):
U r most welcome !!
OpenStudy (shamim):
Anyway may i know the name of ur country?
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OpenStudy (shamim):
Just for curiosity