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Mathematics 11 Online
OpenStudy (anonymous):

Which of the following ordered pairs represents the solution to the system given below? 2x + y = 20 4x − 2y = 40 A) (10,0) B) (0,10) C) (4,2) D) (10, -10)

OpenStudy (anonymous):

If you are under pressure try brute force: Put for x the first number out of each of the pairs and the second for y into the first equation and see whether it fits. A successful candidate (for x and y) for the first equation is then used for the second as well. Once it has worked out for both you know which one it is.

OpenStudy (anonymous):

For multiple choice it is often a quick solution. Be warned that your prof would probably prefer the elimination approach (Gauss) however.

OpenStudy (anonymous):

And the bad retriceway of solving it is via formulating it as LP (linear programming) model. Here a sample (for Gurobi): def main(): pass if __name__ == '__main__': main() from gurobipy import * m = Model("mip1") x = m.addVar(vtype=GRB.CONTINUOUS, name="x", lb=-GRB.INFINITY, ub=GRB.INFINITY) y = m.addVar(vtype=GRB.CONTINUOUS, name="y", lb=-GRB.INFINITY, ub=GRB.INFINITY) m.update() c1 = m.addConstr(2 * x + y == 20, name="1") c2 = m.addConstr(4 * x - 2 * y == 40, name="2") m.update() m.setObjective(x, GRB.MAXIMIZE) m.optimize() print "_________________________________________________________" if m.Status == GRB.OPTIMAL: m.printQuality() m.printAttr('x') m.printAttr(['lb','ub']) print('Obj: %g' % m.objVal) print ('FeasibilityTol: %g' % m.Params.FeasibilityTol) print "\nConstraint checkup:" for c in m.getConstrs(): row = m.getRow(c) LHS = row.getConstant() for i in range(row.size()): LHS += row.getCoeff(i) * row.getVar(i).X if((c.Sense == '=')) & (abs(c.RHS-LHS)>m.Params.FeasibilityTol) | (c.Sense=='<') & (LHS>c.RHS+m.Params.FeasibilityTol) | ((c.Sense=='>') & (LHS<c.RHS-m.Params.FeasibilityTol)): print "Violation in constraint " + c.ConstrName + ": LHS = " + str(LHS) + ", RHS = " + str(c.RHS) else: print "LHS: " + str(LHS)+ " consists of: " for i in range(row.size()): print " " + str(row.getCoeff(i)) + ' * ' + str(row.getVar(i).X) print "________" else: print m.Status

OpenStudy (anonymous):

Here is the output of your problem. I've replaced the value for X through XXXXXXX. Which way would you like to go? *** Python 2.7.9 (default, Dec 10 2014, 12:28:03) [MSC v.1500 64 bit (AMD64)] on win32. *** >>> *** Remote Interpreter Reinitialized *** >>> [Dbg]>>> Optimize a model with 2 rows, 2 columns and 4 nonzeros Coefficient statistics: Matrix range [1e+00, 4e+00] Objective range [1e+00, 1e+00] Bounds range [0e+00, 0e+00] RHS range [2e+01, 4e+01] Presolve removed 2 rows and 2 columns Presolve time: 0.05s Presolve: All rows and columns removed Iteration Objective Primal Inf. Dual Inf. Time 0 1.0000000e+01 0.000000e+00 0.000000e+00 0s Solved in 0 iterations and 0.05 seconds Optimal objective 1.000000000e+01 _________________________________________________________ Solution quality statistics for model mip1 : Maximum violation (unscaled/scaled): Bound : 0.00000000e+00 / 0.00000000e+00 Constraint : 0.00000000e+00 / 0.00000000e+00 Dual : 0.00000000e+00 / 0.00000000e+00 Variable x ------------------------- x XXXXXXXXXXXXXX Variable lb ub -------------------------------------- x -1e+100 1e+100 y -1e+100 1e+100 Obj: 10 FeasibilityTol: 1e-06 Constraint checkup: LHS: 20.0 consists of: 2.0 * 10.0 1.0 * 0.0 ________ LHS: 40.0 consists of: 4.0 * 10.0 -2.0 * 0.0

OpenStudy (anonymous):

im so lost

OpenStudy (anonymous):

As a hint: By looking at the first equation it is obvious that you have to have for x something that when doubled would equals to 20 and at the same time the y should have no impact at all. The A is already quite good candidate therefore (y = 0 and x would give you 20 when doubled). Can you verify, you know just in case...

OpenStudy (anonymous):

The test to verify that A is the solution could look like this: A: x = 10; y = 0; Your equations as follows: 2x + y = 20 4x − 2y = 40 We substitute the x and y through the values we suspect would fit: 2 * 10 + 0 = 20 4 * 10 − 2 * 0 = 40 Can you calculate and check that the terms are really equal to 20 and 40 resp? If do I would be confident that A is what you are looking for.

OpenStudy (anonymous):

Have to go... I hope it helps. I will have a look in ~10 hours again. Good luck!

OpenStudy (kidrah69):

You just made it more confusing for the asker .-.

OpenStudy (kidrah69):

-2(2x + y = 20) 4x − 2y = 40 Keep in mind opposites cancel out :) -4x-2y=-40 -4x-2y=-40

OpenStudy (anonymous):

im really lost @kidrah69

OpenStudy (kidrah69):

We did the Elimination method

OpenStudy (kidrah69):

Opposites cancel :) do u kinda get it?

OpenStudy (anonymous):

not really

OpenStudy (kidrah69):

get it? :-)

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