What is the third term in the expansion of (x + 2)^6?
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OpenStudy (campbell_st):
do you know about binomial theory..?
OpenStudy (kaylardz0405):
replace x for 3 and solve
OpenStudy (anonymous):
umm not really
OpenStudy (anonymous):
oh ok
OpenStudy (campbell_st):
ok... so can you calculate a combination...?
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OpenStudy (anonymous):
so x = the term, right?
OpenStudy (kaylardz0405):
yes
OpenStudy (anonymous):
so the answer is 15625?
OpenStudy (kaylardz0405):
correct
OpenStudy (anonymous):
Yay! Thank you both so much!
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OpenStudy (kaylardz0405):
your welcome
OpenStudy (campbell_st):
ok... so this question uses combinations to calculate part of the coefficient of the term
in a degree 6 expansion you will end up with 7 terms...
the terms start
\[t_{0}, t{1}, t_{2}.....,t_{6}\]
so the 3rd term will have r = 0
then the term is found using
\[^6C_{2} (x)^{6 - 2} \times (2)^2\]
simplify it and you will have the 3rd term
OpenStudy (campbell_st):
oops should read the 3rd term has r = 2
so then the term is
\[^6C_{2} \times x^{6 -2} \times 2^2\]
OpenStudy (anonymous):
so KaylaRdz0405 is wrong?
OpenStudy (campbell_st):
it follows pascals' triangle
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