Question

HELP
A person standing at point C measures the angle of elevation to a point, A, at the top of a perpendicular cliff, to be 18°. After moving 2,200 feet directly toward the foot of the cliff, the person measures the angle of elevation to point A as 56°.

Answer 1

what is the height of the cliff? @surjithayer

Answer 2

\[\frac{ h }{ 2200+DB }=\tan 18,h=\left( 2200+DB \right)\tan 18 ....\left( 1 \right)\]
\[\frac{ h }{ DB }=\tan 56,DB=h \cot 56....(2)\]
h=2200tan18+DBtan18
h=2200 tan18+h cot56*tan 18
h(1-cot 56*tan 18)=2200*tan 18
\[h=\frac{ 2200*\tan18 }{ 1-\cot 56*\tan 18 }=?\]

Answer 3

remember
cot 56=cot(90-34)=tan 34

Answer 4

0.559=.55919=0.6745 ?? @surjithayer

Answer 5

\[h=\frac{ 2200*\tan 18 }{ 1-\tan 34*\tan 18 }=?\]