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Mathematics 7 Online
OpenStudy (anonymous):

Find the numerical value of the trig function..

OpenStudy (anonymous):

cos x = cot x whats csc x = ?

OpenStudy (anonymous):

i know that cosx/cotx =cosx * (sinx/cosx) =sinx

OpenStudy (campbell_st):

well rewrite the 1st statement \[\frac{\cos(x)}{1} = \frac{\cos(x)}{\sin(x)}\] what's the value of sin(x) and then you can find csc(x)

OpenStudy (anonymous):

and i also know that sinx is equal to 1/csc x

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (campbell_st):

you have equivalent fractions... with the numerators the same... so that means you can equate the denominators...

OpenStudy (anonymous):

not really sure where we're going with this. so what does that make csc x = ??

OpenStudy (campbell_st):

look that the fractions when you rewrite the initial statement \[\frac{\cos(x)}{1} = \frac{\cos(x)}{\sin(x)} \]

OpenStudy (campbell_st):

\[\frac{\cos(x)}{1} = \frac{\cos(x)}{\sin(x)}~~~is~~~ \cos(x) = \cot(x)\]

OpenStudy (anonymous):

i understand that.. lol what i dont understand is how we're gonna figure out what csc equals

OpenStudy (campbell_st):

well if you know sin(x) = 1 csc = 1/sin(x) so its csc(x) = 1/1

OpenStudy (anonymous):

okay thats what i thought it was thank you

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