Question

Indices and Logarithms
@rational

Answer 1

Given that \[\log_34=1.26,find~the~value~of~each~of~the~following.\]
\[a)\log_\sqrt{3}36\]

Answer 2

36 = 4 *9
9 = 3^2

Answer 3

is it like this?\[=\frac{ \log_336 }{ \log_3\sqrt{3} }\]

Answer 4

i think that works 2 changing bases

Answer 5

\[=\frac{ \log_39\times~\log_34 }{ \frac{ 1 }{ 2 }\log_33 }\]

Answer 6

\[\huge 36=2^23^2=2^2\sqrt3^4\] is a start

Answer 7

or better yet just
\[36=4\times \sqrt3^3\] take the log base \(\sqrt3\) of that one, expand as a sum of logs and you get it quickly