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What is the polynomial function of least degree with integral coefficients that has zeros 2 and 3i?
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To find the polynomial with the least roots, multiply all the zero terms together If the roots were 1, -5, and 7, you could find it by expanding (x - 1)(x + 5)(x - 7)
But with yours, you have an imaginary term. One of the rules with imaginary terms is that if b*i is a root, then -bi must also be a root. So, your final zeroes are: 2, 3i, and -3i
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