Given that the horizontal distance from the hoop to the free-throw line (at point A) is 15 feet, how tall is the hoop? Round the answer to the nearest whole foot. A. 8 feet B. 10 feet C. 12 feet D. 23 feet
Is there something missing here?
Like point A ??
|dw:1432484788448:dw| To complete the problem, we need the Diagonal distance from the free-throw line to the hoop: $$ \text{Height=}\sqrt{\text{Diagonal}^2-15^2} $$
@ybarrap excellent picture @liljizzet the length of the diagonal as stated above or the angle of elevation (theta) is needed tan theta = height/horizontal so height = 15 tan theta
I am guessing that the height of the hoop is some standard value, so the problem is see if the student knows how to "Google" Gee!
Regulation height is 10 ft.
@radar but that's what the question is asking isn't it?
@triciaal Yes, that was the point I was trying to make (see the 4th post above). If that was all the information provided the author was testing the resourcefulness of his students (I guess lol).
Thanks @triciaal. I think you are both right - that's the only approach that is plausible
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