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Mathematics 14 Online
OpenStudy (anonymous):

Given that the horizontal distance from the hoop to the free-throw line (at point A) is 15 feet, how tall is the hoop? Round the answer to the nearest whole foot. A. 8 feet B. 10 feet C. 12 feet D. 23 feet

OpenStudy (radar):

Is there something missing here?

OpenStudy (radar):

Like point A ??

OpenStudy (ybarrap):

|dw:1432484788448:dw| To complete the problem, we need the Diagonal distance from the free-throw line to the hoop: $$ \text{Height=}\sqrt{\text{Diagonal}^2-15^2} $$

OpenStudy (triciaal):

@ybarrap excellent picture @liljizzet the length of the diagonal as stated above or the angle of elevation (theta) is needed tan theta = height/horizontal so height = 15 tan theta

OpenStudy (radar):

I am guessing that the height of the hoop is some standard value, so the problem is see if the student knows how to "Google" Gee!

OpenStudy (radar):

Regulation height is 10 ft.

OpenStudy (triciaal):

@radar but that's what the question is asking isn't it?

OpenStudy (radar):

@triciaal Yes, that was the point I was trying to make (see the 4th post above). If that was all the information provided the author was testing the resourcefulness of his students (I guess lol).

OpenStudy (ybarrap):

Thanks @triciaal. I think you are both right - that's the only approach that is plausible

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