Question

solve the equation. identify any extraneous solutions. square root of "a"=-2
A. 4 is a solution of the original equation
B. 4 is a solution of the original equation. -4 is an extraneous solution
C. -4 is a solution of the original equation. -4 is an extraneous solution
D. no solution
Simplify the radical expression by rationalizing the denominator. 5/ square root of 30
A. 30/ square root of 5
B. square root of 30
C. square root of 180/30
D. square root of 30/6

Answer 1

\[\huge\rm \sqrt{a} = -2\]
do you know how to solve for a ?

Answer 2

no

Answer 3

to cancel square root you have t o take square both sides
square root can be written as 1/2 exponent
so when you take square root \[\huge\rm \sqrt{x} = (x)^\frac{1}{2}\]
\[\huge\rm \sqrt{x} = ((x)^\frac{1}{2})^2\]
\[\huge\rm x^{\frac{1}{\cancel{2}} \times \cancel{2}}\]
= x
so that's why take square both side so you can cancel out square root

Answer 4

oh

Answer 5

yeah so take square both side let me know what you get :-)

Answer 6

I got b

Answer 7

\[(\sqrt{a})^2 = (-2)^2\]
a = 4
extraneous solution
when you plug in a value into the original equation if you get equal sides then 4 isn't extraneous solution
if both sides are not equal then 4 is extraneous solution

Answer 8

a = 4
so \[\sqrt{4} = -2\]
both sides are equal ?

Answer 9

LAG >.<