Question

URGENT HELP! WILL FAN + MEDAL

Answer 1

What is the question?

Answer 2

I think it's C because of the multiplication of the signs and numbers

Answer 3

@Kash_TheSmartGuy what about #2? (:

Answer 4

I'll give you a clue:\[\frac{ a.b }{ b.c }=\frac{ a }{ c }.\frac{ b }{ b }=\frac{ a }{ c }.1=\frac{ a }{ c }\]

Answer 5

@EmmaTassone so A?

Answer 6

nope

Answer 7

who is b in that equation?

Answer 8

-3?

Answer 9

(x-3)

Answer 10

you can cancel that term from the division, because its repeated in the numerator and denominator

Answer 11

so then that leaves (x-2)/(x-3) so it'll be C?

Answer 12

right

Answer 13

but Formally none of those option are correct

Answer 14

even thought D is "equal" to (x-3)(x-2)/(x+3)(x-3), its not properly equal because D represents a function which has no problem when x=3, when the given funtion its no defined when x=3. so X=3 belongs to the Domain of funtion of letter D but its not belong to the domain of the given funtion.

Answer 15

So the answer would be letter D but its not exactly equal.

Answer 16

can you help me with #2?

Answer 17

I was trying to help you to see that:\[\frac{ (x-3).(x-2) }{ (x+3)(x-3) }=\frac{ (x-3) }{ (x-3) }.\frac{ (x-2) }{ (x+3) }=1.\frac{ (x-2) }{ (x+3) }=\frac{ x-2 }{ x+3 }\]

Answer 18

in #2 you have to look for the roots of the cuadratic function and see when the function becomes zero.

Answer 19

when you want to see the domain restriction of a function you have to see for which values the function its not defined

Answer 20

for example: in the funtion (x-2)/(x+3) when x=-3 we have:\[\frac{ -3-2 }{ -3+3 }=\frac{ -5 }{ 0 }\]
since you cant divide by zero the point x=-3 dont belongs to the domain of the function (x-2)/(x+3)

Answer 21

so how would we find out the answer if the question is confusing? (:

Answer 22

the question is not confusing for #2

Answer 23

would the q^2 cancel out?

Answer 24

neither is for #1, i was just saying that the one who gave you that question could have made a mistake thinking that the given funtion is equal to D, when it isnt exaclty equal.

Answer 25

no, do you know how to factorize a cuadratic funtion?

Answer 26

not really lol

Answer 27

then you should test for which values the quadratic funtion in the denominator its no defined, i mean for which values the funtion become zero.

Answer 28

For example if you replace q=1 in the given expression the denominator dont become zero, so letter a) cant be in the domain restriction

Answer 29

prove with the others

Answer 30

so C?

Answer 31

yeah

Answer 32

so #1 is D and #2 is C