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Find all the values X for the equation below (x+1)^2-25/9=0
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start with \[(x1)^2=\frac{25}{9}\] then take the square root of both sides, don't forget the \(\pm\)
oops i meant \[(x+1)^2=\frac{25}{9}\]
you know the square root of 25 right? also the square root of 9?
yeah
5 and 3
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HI!!
you now have two equations to solve : \[x+1=\frac{5}{3}\] and also \[x+1=-\frac{5}{3}\] then you are done
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