can log
\[\log_{5} 8 = \ln 8 / \ln 5\]
are they equalivent
yup
100% @OOOPS ? it can also be rewritten as log8/log5 right?
yup again and 100%
you can check by hitting your calculator. hit ln, then hit log with ANY BASE. As long as you hit the same base on log, you are ok. I mean ln / ln , log_3/ log_3. DON'T PUT ln/ log_3.
\[\ln x = \log_e x = \frac{\log x}{\log e} \]So,\[\frac{\ln 8}{\ln 5} = \frac{\frac{\log 8}{\log e}}{\frac{\log 5}{\log e}} = \frac{\log 8}{\log e}\times \frac{log e}{\log 5} = \frac{\log 8}{\log 5} = log_5 8\]
What you need to know is \(\log_ab = \frac{log b}{log a}\)
$$\Large \frac{\log_{~a} 8}{ \log_{~a} 5 }= \frac{\ln 8 }{\ln 5}=\frac{\log_{~10} 8}{ \log_{~10} 5 } $$
just double checking, you use log to mean log base 10
i have seen log by itself to mean log base e, sorry i dont mean to confuse the OP
Now, this is complicated. It can be of base 10, base 2, base 100000, or base k, for some (real?!) numbers k. Would be better to write the identity as \(\large \log_a b = \frac{\log_kb}{\log_k a}\) Yes, when I took a math course organized by engineering department, my professor wrote log instead of ln for log base e. He said in advanced mathematics, we used natural log instead of common log, and log in our course means ln.
the only restriction here, k > 0
does a negative base make sense
a positive real number which is not equal to 1
that makes sense, since 1 to any power stays 1. thank you for clarifying
np :) Thanks too for your questions!
Join our real-time social learning platform and learn together with your friends!