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The magnitude of an earthquake is found by the equation M=2/3 log E/10^118, where M is the magnitude and E is the energy released. Find the magnitude of an earthquake that released 10^203 ergs of energy.
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\[M = \frac{2}{3} \log{\frac{10^{203}}{10^{118}}} \] Is this correct?
And that is a base 10 log, right, not a natural log?
yeah, I just need help solving it
Okay, can you simplify\(\frac{10^{203}}{10^{118}}\)?
no?...
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How about \(\frac{10^3}{10^1}\), what does that equal?
100
Right, 100 is \(10^2\) or \(10^{3-1}\) so subtract the powers.
ok so it'd be 10^85
Cool. So what is \(\log_{10}{10^{85}}\)?
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85
You good from here?
yes tysm
Cheers
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