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OpenStudy (anonymous):
If an atom of 14/6 C were to undergo nuclear decay by the emission of a beta particle, which nuclide would result? 10/3 Li 10/5 B 14/7 N 18/8 O
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OpenStudy (cwrw238):
Beta particles are electrons which are negatively charged
OpenStudy (cwrw238):
the atomic number of the resultant nuclide would be 6 -(-1) = 7 so you would get 14/7 N
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