What is the probability of getting a number of less than 3 on 6 out of 10 tosses of a fair die?
How would I set this up using binomial probability?
@butterflydreamer
i'm sorry but i can't help you :( I haven't studied binomial probability yet ....GOOD LUCK on this question though :))!
np thank you :)
A die has numbers : \(\{1, 2, 3, 4, 5, 6\}\) We call it a success if we get less than 3 : \(\{1, 2\}\) So probability of success, \(p = 2/6 = 1/3\) Since we're rolling it 10 times, \(n=10\) \[P(X=6)~~ =~~ \binom{10}{6}(1/3)^6 (1-1/3)^{10-6}\] http://www.wolframalpha.com/input/?i=%5Cbinom%7B10%7D%7B6%7D%281%2F3%29%5E6+%281-1%2F3%29%5E%7B10-6%7D&dataset=
\[\large 10C6 \times \frac{1}{3}^{6}\times\frac{2}{3}^{4}\]
Got it, thanks
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