Write each expression in the standard form for a complex number, a + bi. a. [3(cos(27°)) + isin(27°)]^5 b. [2(cos(40°)) + isin(40°)]^6
@Babynini
@rvc
what radian does cos27(degrees) relate too?
Next, what does sin(27degrees) relate too in terms of radian?
one sec..
kk :) these are kind of meh numbers :| haha
(rvc, if you could take this one that would be fantastic. I have like a 10 pg essay due tomorrow an i'm on the second page xD) Shorty, I shall try to help you as long as I can!
@perl, @rational
ok
@rvc
are you asking me what 27 degrees is in radian or are you asking me what cos(27 degrees) and sin(27 degrees) equal in radians?
what cos(27) and sin(27) equal. Basically what we want to do is replace cos(27) an sin(27) by their equals. let's say (hypothetically) you had [3(cos(90) +isin(90))]^5 cos of 90 = 0 an sin 90= 1 plugging that into this equation would look like: [3(0)+i(1)]^ 5 which makes it soo much simplier. does that make sense?
yeahh
err but your numbers are sketchy because they don't correlate to an exact easy radian on the circle o_o
@IrishBoy123
is this right? cos (27 degrees) = .89100652418 = 0.89 sin (27 degrees) = .45399049974 = 0.45
yep that's correct! :)
err so now I would replace the sin an cos in your equation, and multiply the 3 in
Do i use the rounded decimals or the full ones?
and what about "i"?
full ones
it's a + bi form :) so the i stays
ok
[2.67 + 1.36i]^5 should be your answer so far. I'm not sure what to do with that ^5 though o.o
Yeah, that's what I got. @rvc , do you know what to do next?
good luck with the rest! :) hope someone helps soon hah
thanks
(you can start working on the second one and get to that same point)
ok
can you help me @rvc
@IrishBoy123
@BellaWolfe
@rational @perl please help
aye! yes shorty?
can you help solve the rest of the problem?
...what do i do with the rest of the problem? cross multiply? divisible quadrilaterals?
nvm
aye! im dumb...remember that! ^~^ good luck! beste Wünsche zu Ihnen Shorty ...
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