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Mathematics 17 Online
OpenStudy (anonymous):

Write each expression in the standard form for a complex number, a + bi. a. [3(cos(27°)) + isin(27°)]^5 b. [2(cos(40°)) + isin(40°)]^6

OpenStudy (anonymous):

@Babynini

OpenStudy (anonymous):

@rvc

OpenStudy (babynini):

what radian does cos27(degrees) relate too?

OpenStudy (babynini):

Next, what does sin(27degrees) relate too in terms of radian?

OpenStudy (anonymous):

one sec..

OpenStudy (babynini):

kk :) these are kind of meh numbers :| haha

OpenStudy (babynini):

(rvc, if you could take this one that would be fantastic. I have like a 10 pg essay due tomorrow an i'm on the second page xD) Shorty, I shall try to help you as long as I can!

OpenStudy (babynini):

@perl, @rational

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

@rvc

OpenStudy (anonymous):

are you asking me what 27 degrees is in radian or are you asking me what cos(27 degrees) and sin(27 degrees) equal in radians?

OpenStudy (babynini):

what cos(27) and sin(27) equal. Basically what we want to do is replace cos(27) an sin(27) by their equals. let's say (hypothetically) you had [3(cos(90) +isin(90))]^5 cos of 90 = 0 an sin 90= 1 plugging that into this equation would look like: [3(0)+i(1)]^ 5 which makes it soo much simplier. does that make sense?

OpenStudy (anonymous):

yeahh

OpenStudy (babynini):

err but your numbers are sketchy because they don't correlate to an exact easy radian on the circle o_o

OpenStudy (babynini):

@IrishBoy123

OpenStudy (anonymous):

is this right? cos (27 degrees) = .89100652418 = 0.89 sin (27 degrees) = .45399049974 = 0.45

OpenStudy (babynini):

yep that's correct! :)

OpenStudy (babynini):

err so now I would replace the sin an cos in your equation, and multiply the 3 in

OpenStudy (anonymous):

Do i use the rounded decimals or the full ones?

OpenStudy (anonymous):

and what about "i"?

OpenStudy (babynini):

full ones

OpenStudy (babynini):

it's a + bi form :) so the i stays

OpenStudy (anonymous):

ok

OpenStudy (babynini):

[2.67 + 1.36i]^5 should be your answer so far. I'm not sure what to do with that ^5 though o.o

OpenStudy (anonymous):

Yeah, that's what I got. @rvc , do you know what to do next?

OpenStudy (babynini):

good luck with the rest! :) hope someone helps soon hah

OpenStudy (anonymous):

thanks

OpenStudy (babynini):

(you can start working on the second one and get to that same point)

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

can you help me @rvc

OpenStudy (anonymous):

@IrishBoy123

OpenStudy (anonymous):

@BellaWolfe

rvc (rvc):

@rational @perl please help

OpenStudy (anonymous):

aye! yes shorty?

OpenStudy (anonymous):

can you help solve the rest of the problem?

OpenStudy (anonymous):

...what do i do with the rest of the problem? cross multiply? divisible quadrilaterals?

OpenStudy (anonymous):

nvm

OpenStudy (anonymous):

aye! im dumb...remember that! ^~^ good luck! beste Wünsche zu Ihnen Shorty ...

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