Question

Co-ordinate Geometry

Answer 1

What

Answer 2

\(\large \color{black}{\begin{align} &\normalsize \text{The area of triangle is 5 sq units} \hspace{.33em}\\~\\
&\normalsize \text{Two of its vertices are } (2,1) \normalsize \text{and }(3,-2) \hspace{.33em}\\~\\
&\normalsize \text{the third vertex lies on }y=x+3.\hspace{.33em}\\~\\
&\normalsize \text{Find the third vertex }\hspace{.33em}\\~\\

\end{align}}\)

Answer 3

\(\large \color{black}{\begin{align} &a.)\left(\dfrac53,\dfrac{13}{3}\right)\hspace{.33em}\\~\\
&b.)\left(\dfrac72,\dfrac{13}{2}\right)\hspace{.33em}\\~\\
&c.)(3,4)\hspace{.33em}\\~\\
&d.)(1,2)\hspace{.33em}\\~\\
\end{align}}\)

Answer 4

The only point that lies on y=x+3 is b.

Answer 5

u found that by using options

Answer 6

let the coordinates of the third vertex be (a,a+3) [ from the straight line ]
just write the coordinates in the determinant form and equate it for the area

Answer 7

one easy trick is that if U have option which satisfy the line is answer .
Or use area of triangle let co-ordinate of third vertices's be (x,y)=(x,x+3)

Answer 8

\(\large \color{black}{\begin{align} 5=\dfrac{a(1+2)-2(a+3+2)+3(a+3-1)}{2}\hspace{.33em}\\~\\
\end{align}}\)