Consider the equation for the combustion of methanol: CH3OH + 3O2 2CO2 + 4H2O. If 265g of CO2 is produced in this reaction, what mass of methanol was required? (assume excess oxygen)

Question

Consider the equation for the combustion of methanol: CH3OH + 3O2  2CO2 + 4H2O.  If 265g of CO2 is produced in this reaction, what mass of methanol was required?  (assume excess oxygen)

yadu123 · Answer

Didnt mean to close it

joannablackwelder · Answer

Haha, no worries. So, the idea is to use the molar mass of CO2 to find moles of CO2.

joannablackwelder · Answer

Then use the molar ratio from the balanced reaction to find moles of methanol.

yadu123 · Answer

Co2 is 44 moles

joannablackwelder · Answer

Then use the molar mass of methanol to convert to grams of methanol.

yadu123 · Answer

Can you guide me through this its been a long time since ive done this

joannablackwelder · Answer

I think you mean that CO2 is 44 grams/mol (molar mass) Right?

yadu123 · Answer

yeah

joannablackwelder · Answer

Ok, cool. So, we need to use that number to cancel out the grams unit and leave us with the moles.

joannablackwelder · Answer

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joannablackwelder · Answer

We need to put grams in the denominator, so that cancels

yadu123 · Answer

ok

joannablackwelder · Answer

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