Question

Which is the equation of the line passing through the points A(3, -3) and B(-4, 11)?

Answer 1

@TheAsker2002
@freckles
@Whitemonsterbunny17
@tallymark124
@rishavraj
@dan815

Answer 2

@AlicaIsCray

Answer 3

@Rachell_jpg

Answer 4

Fan and medals at the ready

Answer 5

is there a picture?

Answer 6

Nope (word problems URG!!!)

Answer 7

okay i still can help

Answer 8

@Mateaus your awesome although any ideas math related?

Answer 9

@Question_Asker
@SamsungFanBoy
@SavineTwist
@BellaWolfe

Answer 10

First you need to solve for the slope of the problem.

Answer 11

okay, what is the best way to do that?

Answer 12

formula to find slope
where x and y values are
(x1,y1)(x2,y2)

Answer 13

okay so the slope is negative 2...

Answer 14

yeah

Answer 15

what would i need to do next

Answer 16

Then you would plug in one of the original points as y and x and solve for b. Then rewrite the equation with the slope and the value you found for b.

Answer 17

? wait what, im sorry what do i do?

Answer 18

It's okay. Do you know what slope-intercept formula is? y=mx+b

Answer 19

now i do lol

Answer 20

Haha it's all good. Do you understand what to do?

Answer 21

so plug in -2 as Y into (Y=mx+B
)

Answer 22

No. -2 is the slope. In y=mx+b, b is the y intercept and m is the slope. You would plug in -2 as m and then use one of the original points as x and y. Does that make sense?

Answer 23

so it would look like Y=-2x=b?

Answer 24

Not quite. It's supposed to be +b at the end. But other than that, yes.

Answer 25

oh duh sorry

Answer 26

It's okay. Then you plug in one of the two original points for x and y in order to solve for b.

Answer 27

y = -2x + 3?

Answer 28

Yep!

Answer 29

that would be my final answer right

Answer 30

yeah

Answer 31

Thank you so much jessliynP

Answer 32

that was a big one

Answer 33

You're welcome. :)

Answer 34

Believe it our not im decent at math so message me any time i will do my best to return the favour :)

Answer 35

Okay.

Answer 36

Actually, do you happen to know how to find real or complex zeros of problems??

Answer 37

are you talking about inside of a polynolial?

Answer 38

ummmm.... maybe?? I think so.....

Answer 39

the problem is f(x)=x^3+7x^2+9x-5
and I know that one of the zeros is x=-5

Answer 40

https://www.youtube.com/watch?v=mSBT3oqOoJs (I watch this guy from time to time) Very helpful

Answer 41

okay. thanks! i'll try this....

Answer 42

im short on time so i wont explain but your answer can be....
1) x = 5
2) x =(2-√8)/2=1-√ 2 = -0.414
3) x =(2+√8)/2=1+√ 2 = 2.414

Answer 43

@JessilynP

Answer 44

Isn't it -5

Answer 45

you might be right molly?

Answer 46

so i use the quadratic formula???

Answer 47

substitute the one by one
(-5)^3+7(-5)^2+9(-5)-5
the expression is equal to 0 so x=-5 is a root of the polynomial
so now divide the polynomial by (x+5)
I think it would be
x=-5
-1+sqrt2
-1-sqrt2

Answer 48

okay......? wait, do I use the quadratic formula for this problem?

Answer 49

you can use synthetic division
(x^3+7x^2+9x-5)/x+5

Answer 50

okay

Answer 51

so i would get x^2+2x-1?

Answer 52

any expression divided by 1 is the expression so it would be
x^2+2x-1*1
then write it as a set of linear factors

Answer 53

x^2+2x-1*1

Answer 54

okay. so as a final answer i would get −1±√2

Answer 55

yes! also -5

Answer 56

okay. thank you!!!

Answer 57

x=-5, −1±√2

Answer 58

thank you so so so much! :)

Answer 59

ur welcome

Answer 60

wow good job molly that was impressive!!! @MollyhatesMath @JessilynP
This was one of the most helpful threads ive everseen on open study