A mechanic uses a mechanical lift to raise a car. The car weighs 11,000 N. The lift raises the car 2.5 m. How much work is required to accomplish this task? A. 4400 J B. 22,500 J C. 2.27 x 10-4 J D. 27,500 J
@JoannaBlackwelder
W=Fd
whats FD?
F is force and d is displacement (F and d have to be in parallel directions.)
how do we figure that out if they didnt give it to us ?
W is the energy or work so that is joules. F is the force or the weight so Newtons. D is Displacement so Meters.
The movement is in the y-direction since the problem says that the car is being lifted.
you would plug 11,000 and 2.5 into the equation to get the work
And the weight of the car is the force that must be overcome to move the car vertically.
Which is being pulled vertically by gravity.
so its A?
no it would be 11,000 times 2.5 not divided so it would be D
ohhhh
When 2 variables are next to each other they multiply.
:-)
ohh ok thanks
You're welcome
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