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Chemistry 9 Online
OpenStudy (anonymous):

A mechanic uses a mechanical lift to raise a car. The car weighs 11,000 N. The lift raises the car 2.5 m. How much work is required to accomplish this task? A. 4400 J B. 22,500 J C. 2.27 x 10-4 J D. 27,500 J

OpenStudy (anonymous):

@JoannaBlackwelder

OpenStudy (joannablackwelder):

W=Fd

OpenStudy (anonymous):

whats FD?

OpenStudy (joannablackwelder):

F is force and d is displacement (F and d have to be in parallel directions.)

OpenStudy (anonymous):

how do we figure that out if they didnt give it to us ?

OpenStudy (deving7240):

W is the energy or work so that is joules. F is the force or the weight so Newtons. D is Displacement so Meters.

OpenStudy (joannablackwelder):

The movement is in the y-direction since the problem says that the car is being lifted.

OpenStudy (deving7240):

you would plug 11,000 and 2.5 into the equation to get the work

OpenStudy (joannablackwelder):

And the weight of the car is the force that must be overcome to move the car vertically.

OpenStudy (joannablackwelder):

Which is being pulled vertically by gravity.

OpenStudy (anonymous):

so its A?

OpenStudy (deving7240):

no it would be 11,000 times 2.5 not divided so it would be D

OpenStudy (anonymous):

ohhhh

OpenStudy (deving7240):

When 2 variables are next to each other they multiply.

OpenStudy (joannablackwelder):

:-)

OpenStudy (anonymous):

ohh ok thanks

OpenStudy (deving7240):

You're welcome

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