A mechanic uses a mechanical lift to raise a car. The car weighs 11,000 N. The lift raises the car 2.5 m.
How much work is required to accomplish this task?
A.
4400 J
B.
22,500 J
C.
2.27 x 10-4 J
D.
27,500 J
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OpenStudy (anonymous):
@JoannaBlackwelder
OpenStudy (joannablackwelder):
W=Fd
OpenStudy (anonymous):
whats FD?
OpenStudy (joannablackwelder):
F is force and d is displacement (F and d have to be in parallel directions.)
OpenStudy (anonymous):
how do we figure that out if they didnt give it to us ?
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OpenStudy (deving7240):
W is the energy or work so that is joules. F is the force or the weight so Newtons. D is Displacement so Meters.
OpenStudy (joannablackwelder):
The movement is in the y-direction since the problem says that the car is being lifted.
OpenStudy (deving7240):
you would plug 11,000 and 2.5 into the equation to get the work
OpenStudy (joannablackwelder):
And the weight of the car is the force that must be overcome to move the car vertically.
OpenStudy (joannablackwelder):
Which is being pulled vertically by gravity.
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OpenStudy (anonymous):
so its A?
OpenStudy (deving7240):
no it would be 11,000 times 2.5 not divided so it would be D
OpenStudy (anonymous):
ohhhh
OpenStudy (deving7240):
When 2 variables are next to each other they multiply.
OpenStudy (joannablackwelder):
:-)
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