Evaluate \[\lim_{x \rightarrow \frac{ \pi^- }{ 2 }}e ^{tanx}\]
I don't understand why the answer is positive infinity.
\[\huge \lim_{x \rightarrow \frac{ \pi}{ 2 }^-}e ^{\tan(x)}\]
\(e^x\) is a continuous function, so \[\lim (e^{f(x)}) = e^{\lim (f(x))}\]
just trying to read it is all
goes to \(\frac{\pi}{2}\) from the left
|dw:1432605794160:dw|
tangent is going to \(+\infty\)
what @misty1212 said tangent goes to plus infinity so \(e^{\tan(x)}\) goes to infinity real real real fast
Oh okay. Just wondering can I sub in the pi/2 into the tanx? Does that help me?
no
since \(\frac{\pi}{2}\) is not in the domain of tangent you cannot do that
otherwise that would be the right thing to do, but not in this case
So the only way to solve this is to think logically?
heaven forbid
i mean "yes"
|dw:1432606236453:dw|
oh, pi/2 is vertical asymptote
its much worse than that, as you walk from left side it goes to +infinity as you walk from right side it goes to -infinity
so sometimes we say the two sided limit for \(\tan x\) as \(x\to \pi/2\) does not exist
Okay, thank you!
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