Find the domain, range and asymptote of y=10-e^(-x)
missing something ?
whatever it is suppose to be make sure what is inside the log is larger than zero that is all
One sec. Wrong function
\[-x>0\] solve for \(x\)
So x is greater than 0? Domain is x element of the real numbers?
@satellite73
domain is all the x values that you can plug into a function
look at the given expression, are there any x values that make the expression undefined ?
no?
so the domain is all real numbers : \((-\infty,~ +\infty)\)
Okay, how do you get the range?
find the limits as \(x\to+\infty\) and \(x\to -\infty\)
The range is the real numbers?
how ? what did u get for the limits ?
I wasn't really sure if I got the limits... but it looks like it goes infinity and neg. infinity..
"it looks like" is a forbidden phrase in calculus, work the limits and you will be surprised im sure
Oh... Can you please help with one of the limits? Just to make sure I'm doing it correctly..
\[\large{\begin{align} \lim\limits_{x\to+\infty} 10-e^{-x} &= \lim\limits_{x\to+\infty} 10- \lim\limits_{x\to+\infty} e^{-x}\\~\\ &=\lim\limits_{x\to+\infty} 10- e^{\lim\limits_{x\to+\infty}-x}\\~\\ &=10- e^{-\infty}~~*\\~\\ &=10-0\\~\\ &=10\\~\\ \end{align}}\]
so the graph of given function flattens to 10 as you walk extreme right on x axis
work the other limit to find out what happens to the function as you go extreme left
how did e^-infinity turns out to be a zero?
good question, i have used exponent property : \[\large a^{-n} = \frac{1}{a^n}\]
\[\large e^{-\infty} = \frac{1}{e^{\infty}} = \frac{1}{\text{think of very big positive quantity here}} = 0\]
oh I see.
It approaches to zero
So the other limit goes to infinity.
sure ?
does it go to "positive" infinity or "negative" infinity
negative infinity
good, can you guess the range now keep in mind 10-e^(-x) is a continuous function
also it is a strictly increasing function work the first derivative quick if you want
remember how to prove if a function is increasing ?
Not really...
But is the range this (-infinity,10)
In \([a,b]\), if \(f'(x)\) is positive, then \(f(x)\) is a strictly increasing in that interval.
yes range is (-infinity, 10)
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So there's horizontal asymptote on y=10?
Yes, also thats clear from graph
I think I got it from here. Thank you for your help! :)
yw
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