Question

Next question..

Answer 1

so its the same thing find the restrictions.

Answer 2

x^2 +5x+6/x+4 * x^2+x-12/X^2+x-2

Answer 3

i got (x-3)(x+3)/x-1

Answer 4

i just didnt get the restrictions..

Answer 5

its either -2,-4,1 or -2, -4

Answer 6

denominator can't be what ?? o^_^o

Answer 7

Huh.. :/?

Answer 8

forgot *equal* to what ?

Answer 9

denominator can't be equal to 0 right
just like we did ??
\[\huge\rm x-1 \cancel{=}0\]solve for x

Answer 10

ok so 1..

Answer 11

sOoOoOoO..... ?????? ?

Answer 12

-2,-4,1 haha..

Answer 13

what is at the denominator ?

Answer 14

so if the bottom is x-1..

Answer 15

yes right
bottom is x-1
like i said denominator can't be equal to 0
bec you can't divide anything by 0 it would be undefined
\[\huge\rm x-1 \cancel{=}0\]
solve for x

Answer 16

so how do the -2 and -4 take part?

Answer 17

so the 1, would have to be included in the restrictions?

Answer 18

forget about the numerator it's okay if you get 0 at the numerator
0/3 =0
that's fine we are okay with it
the problem is denominator can't be equal to 0
bec \[\huge\rm \frac{ 9 }{ 0 }= undefined \]
you can't divide by 0
so just x-1 can't equal 0
solve for x \[x\cancel{ =} 1\]

Answer 19

Ok got it got it. im just confused if you would say -2,-4, and 1, since you cant equal that

Answer 20

why x can't be 1
bec when you plug in 1 for x
you will get 0 \[\frac{ ? }{ x-1 } = \frac{ ? }{ 1-1 } =\frac{ ? }{ 0 }\]
0 at the bottom not a good sign:(
so that's why \[x \cancel{ = }1 \]

Answer 21

Thank you! :D

Answer 22

my pleasure! o^_^o

Answer 23

its 2am.. and im still doing math :(

Answer 24

aww gO_O tO_O sleep!

Answer 25

Cant, have soo much math to finish! :(

Answer 26

hmm alright gO_Od luck!

Answer 27

Thank you again! ill write you if i need your greater intelligence

Answer 28

my pleasure
and thanks o^_^o .-.