Question

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Answer 1

Use substitution
(8y-12)+12y=68

Answer 2

Can you solve that?

Answer 3

no I'm not sure how to use substitution ( new to all of this)

Answer 4

Alright so basically what i did was....
Since it already gives the valuse for what X equals i plugged it in place of X on the other equation do you get that so far?

Answer 5

Alright so basically what i did was....
Since it already gives the valuse for what X equals i plugged it in place of X on the other equation do you get that so far?

Answer 6

yeah

Answer 7

Ok once i did that we need to combine like terms
\[8y-12+12y=68\]
Do you see any like terms ONLY on the left side that can be combined?

Answer 8

the 12s?

Answer 9

\[\huge\rm 12y+8y=?\]

Answer 10

or the ys? 8y and 12 y?

Answer 11

\[\huge\rm 12+8=?\]

Answer 12

20

Answer 13

\[\huge\rm20y-12=68\]
\[\huge\rm68+12=?\]

Answer 14

80

Answer 15

\[\huge\rm80\div20=?\]

Answer 16

4 so y = 4

Answer 17

yep!
Now substitute that back into equation 2
x=8(4)-12

Answer 18

20

Answer 19

I will try to solve your system of equations.
x=8y−12;x+12y=68
Step: Solve x=8y−12 for x:
Step: Substitute (8y−12) for x in x+12y=68:
x+12y=68
8y−12+12y=68
20y−12=68(Simplify both sides of the equation)
20y−12+12=68+12(Add 12 to both sides)
20y=80
20y/20
80/20
(Divide both sides by 20)
y=4
Step: Substitute (4) for y in x=8y−12:
x=8y−12
x=(8)(4)−12
x=20(Simplify both sides of the equation)

Answer 20

yep :)

Answer 21

thanks for explaining. I really appreciate it :)

Answer 22

No problem :)