Question

If 1.6 moles of an ideal gas are at a temperature of 25°C and a pressure of 0.91 atm Hg, what volume would the gas occupy, in liters?

0.28 L
3.0 L
36 L
43 L
@nechirwan

Answer 1

Just use the ideal gas law: PV = nRT.

P = pressure in atm
V = volume in liters
n = moles of gas
R = gas constant = 0.0821 L atm / K mole
T = Kelvin temperature = 25°C + 273 = 298 K

PV = nRT
V = nRT / P = (1.6)(0.0821)(298) / (0.91) = 43 L