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OpenStudy (anonymous):
Consider this equilibrium: COCL2(g)<-->CO(g)+Cl2(g)Keq=8.1*10^-4 What is true for this system? [COCL2]<[CO][CL2] [COCL2]=[CO][CL2] [COCL2]>[CO][CL2] [COCl2]= 1/[CO][Cl2] [COCL2]=1/[CO]
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OpenStudy (nechirwan):
Ke is the products over the reactants. Since Ka is so small, it must mean that COCl2 has a huge concentration by comparrison. The answer is [COCl2] > [CO][Cl2]
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