Question

MEDAL AND FAN TO WHOEVER ANSWERS!
Part A: What is the approximate length of rod PR? Round your answer to the nearest hundredth. Explain how you found your answer, stating the theorem you used. Show all your work. (5 points)

Part B: The length of rod PR is adjusted to 17 feet. If width PQ remains the same, what is the approximate new height QR of the scaffold? Round your answer to the nearest hundredth. Show all your work. (5 points)

Answer 1

Part a you can use pythagoras
Pq^2+Qr^2=Pr^2
14^2+8^2=pr^2
196+64=pr^2
260=pr^2
Pr=16.1

Answer 2

Use pythagoras again for part b

Pq2+qr2=pr2
14^2+qr2=17^2
196+qr^2=289
Qr2=289-196
Qr2=93
Qr=9.6