A bag contains 4 white, 3 blue, and 5 red marbles. Find the probability of choosing a blue marble, then a red marble if the marbles are replaced.
A. 5/44
B. 15/35
C. 2/3
D. 1/15
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OpenStudy (anonymous):
How many blue marbles are there? How many total marbles are there? And how many red marbles are there?
OpenStudy (anonymous):
3 blue, 12 total, and 5 red.
OpenStudy (anonymous):
So do \[\frac{ blue }{ total }*\frac{ red }{ total }\]
OpenStudy (anonymous):
15/144
OpenStudy (anonymous):
so it is B
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OpenStudy (anonymous):
Well you can simplfy it to 5/48
OpenStudy (anonymous):
but there is no 5/48 on the choices. And how do you simplify?
OpenStudy (anonymous):
Are you sure the question doesn't say that they aren't replaced? Because we have the correct answer right now.
OpenStudy (anonymous):
im sure
OpenStudy (anonymous):
oh it says are not replaced, my bad
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OpenStudy (anonymous):
Well then let's go again\[\frac{ blue }{ total }*\frac{ red }{ total-1 }\]
OpenStudy (anonymous):
15/143?
OpenStudy (anonymous):
\[\frac{ 3 }{ 12 }*\frac{ 5 }{ 11 }\]
OpenStudy (anonymous):
oh
OpenStudy (anonymous):
15/132
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OpenStudy (anonymous):
Now do\[\frac{ 15 }{ 132 }\div \frac{ 3 }{ 3 }\]
OpenStudy (anonymous):
5/44
OpenStudy (anonymous):
Boom, that's your answer
OpenStudy (anonymous):
thank you sooooo much!!!!
OpenStudy (anonymous):
No problem :)
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