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Given the exponential equation 3x = 243, what is the logarithmic form of the equation in base 10? I NEED HELP ASAP
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if you take the log of both sides you get \[\log(3^x) = \log(243)\] apply the log law for powers and it becomes \[x log(3) = \log(243)\] now solve for x
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i am a little rusty on this
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i got x=5
@campbell_st
@bpstation
you don't need to solve... just divide both sides by log(3) \[x \times \log(3) = \log(243)\] then you have x on the left side and the expression for x on the right. your answer choice is incorrect...
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i have to use a different account this is still the same person
So the answer would be A
that's correct
Thank you so much!!
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