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Calculus1 9 Online
OpenStudy (anonymous):

easy question: For which of these series is the Integral Test not appropriate?

OpenStudy (anonymous):

OpenStudy (anonymous):

anyone?

OpenStudy (anonymous):

freckles, please tell me youre going to take a stab at it!

OpenStudy (anonymous):

i think its the last one, since that one seems impossible to integrate i mean look at that thing, ugly as hell lol

OpenStudy (freckles):

Well do you know which of the thingys inside the summation signs is integratable ?

OpenStudy (anonymous):

first one is a log, you could use the integral test for tha

OpenStudy (freckles):

you are right

OpenStudy (freckles):

that last one doesn't seem easy to integrate

OpenStudy (freckles):

but the ones before it are definitely are

OpenStudy (anonymous):

i hate to disagree with my learned colleague @freckles but i think the last one is easy to integrate

OpenStudy (freckles):

well I did say seems

OpenStudy (anonymous):

put \(u=\tan^{-1}(x)\) and you get it right away

OpenStudy (freckles):

I haven't attempt to integrate it

OpenStudy (anonymous):

@freckles, right but it couldnt be that easy right? they probably WANT me to think that its not integratable just because it seems daunting

OpenStudy (anonymous):

i think it might actually be the second one

OpenStudy (anonymous):

i think the point is that finding the antiderivative of cosine doesn't help you any

OpenStudy (freckles):

there are actually conditions in which you can apply the integral test

OpenStudy (anonymous):

@satellite73 ohhhh because it just gives a sin, right?

OpenStudy (anonymous):

you just end up chasing your tail, since you go right to sine, and that is just as unclear as cosine i think the questions isn't which ones you can integrate, but which one will not give you any new info

OpenStudy (anonymous):

@satellite right right

OpenStudy (anonymous):

sorry freckles, satellite's gonna have to get the medal on this one,

OpenStudy (anonymous):

i just wanna thank @freckles and @satellite73, and anyone else on this thread,

OpenStudy (freckles):

and also f has to be decreasing, continuous, and positive on [1,inf)

OpenStudy (anonymous):

this is my first day on openstudy, and man it really is great, very stimulating

OpenStudy (freckles):

and cos(xpi) isn't always positive

OpenStudy (freckles):

and its it always decreasing either

OpenStudy (anonymous):

oh good point kind of forgot about that

OpenStudy (anonymous):

@freckles and @satellite73 , i just got the answers, the cos one was ...wait for it.. CORRECT!

OpenStudy (anonymous):

wait @freckles, then how come it was the right answer? i dont get it. if cos isnt always positive

OpenStudy (freckles):

what?

OpenStudy (freckles):

I agreed that cos was the right answer and I gave my real why it doesn't satisfy the conditions of the integral test which was that it needs to be continuous, positive, and decreasing I said cos(pix) isn't always positive and isn't always decresaing

OpenStudy (freckles):

the conditions aren't met for the cos(pix)

OpenStudy (freckles):

reason (not real) lol

OpenStudy (anonymous):

ohhhh right, whoops, forgot that the question was asking which should NOT use the integral test

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