A 10 gram sample of a substance that's used to detect explosives has a k-value of 0.1356. Find the subtance's half-life, in days.round to the nearest tenth
please help
I will try my best ><. This is chemistry ?
no algebra
okay give me a minute and let me work it out
ok
are you still working it out?
lol yesh, I am questionable about my answer considering I am given no other variables but the constant an mass
I divided 10 by the k-value constant since this seem like rate of decay
10/0.1356
N=Noe^-kt No=initial mass( at time t=0) N=mass at time t k=a positive constant that depends on the substance itself and on the units used to measure time t=time, in days
@LiteLegacy
Sorry can't swing it I'm to unsure ~-~
But insert the value you have Like No=10 for the intial and and K-0.1356
can you tell me what you think it is?
@LiteLegacy
73.7 but that is highly wrong to me ><
@rational
@Loser66
@coolman500
it works as follows: \[\frac{N}{N_o} = \frac {1}{2} = e^{- k t_{half}} \\ \ln ( \frac {1}{2} ) = -\ln ( 2 ) = - k t_{half} \\ t_{half} = \frac{\ln(2)}{k}\] in summary half life = ln(2)/k AND k = ln(2)/half life here you get 5.1 days the mass is a red herring, the half life for a kilo of the stuff should be the same as the half life for a gram.
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