Question

A spinner has three sections. The table shows the results of spinning the arrow on the spinner 80 times.


Three column table. First column values are Section 1 and 28. Second column values are Section 2 and 36. Third column values are Section 3 and 16.


What is the experimental probability of the arrow stopping over Section 1?

A.


B.


C.


D.

Answer 1

1/28 7/20 7/13 4/5

Answer 2

where is table?

Answer 3

the fractions are sperated with spaces

Answer 4

in the middle

Answer 5

Three column table. First column values are Section 1 and 28. Second column values are Section 2 and 36. Third column values are Section 3 and 16.

Answer 6

So. A spinner with tree section, was spun 80 times.

The spinner landed on Section 1, 28 times.
The spinner landed on Section 2, 36 times.
and
The spinner landed on Section 3, 16 times.

Answer 7

tree*three

Answer 8

The experimental probability of landing in section 1, is equal to
the number of times the spinner landed in section 1, divided by the total number of spins.

Answer 9

so here are the answers a.1/28 b.7/20 c.7/13 d.4/5

Answer 10

so set up the ratio (fraction), with the two relevant numbers in the question

Answer 11

so c

Answer 12

What are the relevant numbers:

what is the number of landing in section 1
and what is the total number of spins?

Answer 13

28+36+16=80

Answer 14

What is the number of landings in section 1?

Answer 15

28

Answer 16

good

and the total number of spins is 80


so the experimental probability of landing in section 1, is equal to
28 / 80

Answer 17

simplify this fraction

Answer 18

7/20

Answer 19

Good.

Answer 20

so thats the answer

Answer 21

Yes. now you are done.