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OpenStudy (anonymous):
Basic calc question. I am given the derivative and the value of y at a given x value, can i find this?
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OpenStudy (anonymous):
I know g(5)=-3 and g(5)'=6. I am asked to find the derivative of f(5).
I am told f(x)=[g(x)]^3 . Is this capable of being solved, and if so how.
OpenStudy (rational):
differentiate using chain rule
OpenStudy (rational):
f(x) = [g(x)]^3
f'(x) = ?
OpenStudy (anonymous):
I guessed that but what is the derivative of a floating exponent.
Im sorry if im typing slowly for some reason this site is killing my computer.
OpenStudy (anonymous):
6*3*-3^2?
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OpenStudy (rational):
use this
\[\frac{d}{dx}x^n ~=~n*x^{n-1}\]
OpenStudy (anonymous):
Yeah thats like the first rule of differntation you learn, but does it still appy without a varible x?
OpenStudy (rational):
variables are just dummy
OpenStudy (rational):
\[\large \frac{d}{d\clubsuit} \clubsuit^n ~= ~n*\clubsuit^{n-1} \]
OpenStudy (anonymous):
XD
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OpenStudy (anonymous):
S0 6*3*(-3)^2 would fit that or not?
OpenStudy (rational):
\[ f(x) = [g(x)]^3\]
\[f'(x) = 3*[g(x)]^{3-1} * \color{red}{g'(x)}\]
OpenStudy (rational):
plugin \(x=5\)
OpenStudy (rational):
6*3*(-3)^2 looks good!
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