Ask your own question, for FREE!
Physics 14 Online
OpenStudy (anonymous):

question inside!! :)

OpenStudy (anonymous):

|dw:1432745418519:dw|

OpenStudy (michele_laino):

we can consider the root mean quadratic speed of a molecule of a gas, which is given by the subsequent formula: \[\Large {v_{RMQ}} = \sqrt {\frac{{3RT}}{M}} \]

OpenStudy (michele_laino):

where R is the gas constant, namely R=8.31 J/Kelvin, and M is the molecular mass of our gas. T is the gas temperature of course, measured in Kelvin

OpenStudy (anonymous):

okay! so how can we figure out which object (A,B,C or D) moves the fastest? what do we plug in?

OpenStudy (michele_laino):

I think that we can consider only the temperature, since the molecular mass of those gases are similar each other

OpenStudy (michele_laino):

namely, we have: \[\Large {M_A} \simeq {M_B} \simeq {M_C} \simeq {M_D}\]

OpenStudy (anonymous):

okay!! so 3*temperature? would that mean object D moves the fastest since the solution would be the largest?

OpenStudy (michele_laino):

yes! that's right!

OpenStudy (anonymous):

ooh yay!! thank you:D

OpenStudy (michele_laino):

thank you!! :D

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!