Question

The amount of heat needed to raise 250 g of a substance by 15 K is 2,930 J. What is the specific heat of the substance (J/(kg*K))?

A. 0.78

B. 11,000

C. 780

D. 1.1 × 10^7

**not 100% sure, but is this choice C? 780?

Answer 1

the equation... in case i didn't write it clearly :P

Answer 2

here we have to use this formula:
\[\Large Q = cm\Delta T\]
Q is the heat , c is the specific heat, and T is the absolute temperature

Answer 3

okay! so what would be plugged in? :/

Answer 4

so, we can write:
\[\Large c = \frac{Q}{{m\Delta T}} = ...\frac{{Joules}}{{Kg \times Kelvin}}\]

Answer 5

okay! so 2930/(kg*15)? is that right?

and solve for kg?

Answer 6

no, we have to compute this:
\[\Large c = \frac{Q}{{m\Delta T}} = \frac{{2930}}{{0.250 \times 15}} = ...\frac{{Joules}}{{Kg \times Kelvin}}\]

Answer 7

ohh okay!! so we get 781.333333

so about 780?

Answer 8

that's right!!

Answer 9

yay!! thank you:D

Answer 10

:D