Question

Find the first six terms of the sequence.
a1 = -3, an = 2 ● an-1

Answer 1

if I help will you give me a medal

Answer 2

alright

Answer 3

ok so I will work this out with you is that ok or do u want a direct aswer

Answer 4

work it out

Answer 5

doesn't matter if they want or nah :-)

Answer 6

ok :) so we start with -3 first and whats next to it an = -2 correct so if a1 = -3 and an = -2 then we know we have different orders of operations to work with. and fianally at the end we have an = -1 and again we find out we have a third different order of operation. so the next three will be between 1-3 so positive 3 positive 2 and positive 1 :)

Answer 7

These are my answer choices.
a. -6, -12, -24, -48, -96, -192
b. -3, -6, -12, -24, -48, -96
c. 0, 2, -6, -4, -2, 0
d. -3, -6, -4, -2, 0, 2

Answer 8

a_n is not just 2
it's \[\huge\rm a_n = 2 \times a_{n-1}\]

Answer 9

can you choose multiple of them

Answer 10

n = next term
so to find 2nd term
replace n by 2

Answer 11

so what is a

Answer 12

can you choose multiple answers

Answer 13

no

Answer 14

\[\huge\rm a_n = 2 \times a_{\color{Red}{n}-1}\]
a_1 is first term

Answer 15

given is first term which is -3
so
to find 2nd term replace n by 2 \[\huge\rm a_2 = 2 \times a_{\color{Red}{2}-1}\]
2-1 = 1 now its become a_1
so replace a_1 by -3

Answer 16

okay?
can you keep going?

Answer 17

\[\huge\rm a_2 = 2 \times a_{\color{Red}{2}-1}\]

\[\large \rm a_2 = 2 \times a_{\color{Red}{_1}}\]
a_1 is -3
so plug in
\[\large\rm a_2 = 2 \times -3\]
a_2 = - 2nd term is -6
now try other 3 terms

Answer 18

try to find*

Answer 19

replace n by 3 for 3rd term
replace n by 4 for 4th term
and replace n by 5 for 5th term

Answer 20

so then you do a_3=2*-6 and get -12

Answer 21

right?

Answer 22

yep right

Answer 23

yay thank you sooo much!!!!

Answer 24

np :-)

Answer 25

how are you with summation notation?