Question

Show that x=Be^(µt) is a solution of mx ̈+kx=0

Answer 1

it's not. differentiate it.

Answer 2

I know i differentiated it and didn't get the right answer.

Answer 3

I've been given some more information:
B=Ae^jϕ

Answer 4

and µ=α+jω

Answer 5

better.

but have you differentiated that??

it's suddenly become more complicated!

Answer 6

I'm afraid to try, but i'll give it a go.

Answer 7

lol!
\[x=B e^{µ t} \ : \ B=A e^{jϕ} \ \ : \ µ=α+j ω \\ x=A e^{jϕ} e^{(α+j ω) t}\]
\[x = A e^{α t+j ( ω t + \phi ) }\]

looks interesting!!