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OpenStudy (curry):
OpenStudy (curry):
@nincompoop Please ? I posted twice, I didn't get any help...
OpenStudy (curry):
@myininaya
OpenStudy (curry):
@Preetha @dan815
OpenStudy (curry):
@Zarkon
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OpenStudy (anonymous):
Olmost got it
OpenStudy (curry):
the answer is 2/9. but I don't understand the work behind it. they did
(1/3m)(Mx1 + m(x1+ l/4) + m(x1+l/4+l/2). with x1 being the amount of the book ON the table.
OpenStudy (curry):
@Hero
OpenStudy (anonymous):
sorry cant help
OpenStudy (anonymous):
1/3m( mx1+m(x1+1/4)+m(x1+1/4+1/2)
x1=-1/3, 1/2-1/3= 1/6
1/6 bottom book can over hang
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OpenStudy (curry):
why is the second value x1 + 1/4 though?
OpenStudy (curry):
I would imagine it'd be x1- l/4. right? cause that's the part of the book that's on the table?
OpenStudy (anonymous):
Center of mass of each book at its center
OpenStudy (curry):
mhmm. and then?
OpenStudy (anonymous):
Because furthest right is the center of mass, then take origin st edge postive to right
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OpenStudy (curry):
wait, i don't understand what you're saying exactly, sorry! can you please explain it diferently?