Question

What is the oblique asymptote of the function f(x) = the quantity x squared plus 5x plus 6 over the quantity x minus 4 ?

y = x + 9
y = x - 9
y = x + 1
y = x - 1

Answer 1

\[f(x) = \frac{ x^2 + 5x + 6 }{ x -4 }\]

Answer 2

@ParthKohli @texaschic101 @sleepyjess @rational

Answer 3

please help

Answer 4

do you know polynomial long division?

Answer 5

no like i was absent for a week because i was sick now thisis my make up work and school is almost over i need to learn this to pass the exam

Answer 6

Ok it's basically just dividing number like 10/5 but instead of numbers you are dividing expressions with expressions

Answer 7

the answer is x + 9

Answer 8

because first you have to look at the numerator by segments

Answer 9

k nd btw thnx do you mind if you explain how to do it so if i run across something similar to this on my exam

Answer 10

no problem sure

okay so look at the numanator
look at the x^2 + 5x, you have to multiply the x-4 by something that will give you at least close to x^2 + 5x if not exactly that expression

this is more like saying if you divide 10 by 3 the closest you can bring to 10 is 9 which 3*3

Answer 11

so if you multiply x with (x-4) you will get x^2 + 4x
that is at least a bit close to x^2 + 5x

Answer 12

oh ok so like if we had 5/4 the closest would be like 4/4 or 6/4

Answer 13

yeah exactly

Answer 14

okay thnx i have more do you mind helping me with ill gve medals

Answer 15

I have no problem (as long as I know how to solve it lol)

Answer 16

thnx

Answer 17

np