Question

Parallelogram JKLM has the coordinates J (6, 7), K (12, 7), L (8, 2), and M (2, 2). Which of the following sets of points represents a dilation from the origin of parallelogram JKLM?

A. J' (6, 21), K' (36, 7), L' (24, 2), M' (2, 6)
B. J' (18, 21), K' (36, 21), L' (24, 6), M' (6, 6)
C. J' (18, 7), K' (36, 7), L' (24, 2), M' (6, 2)
D. J' (9, 10), K' (15, 10), L' (11, 5), M' (5, 5)

Answer 1

@mathmate @MrNood

Answer 2

Start with choice A. Compare the coordinates of each new point with the original point. Make sure the same was done to both coordinates of all points

Answer 3

Then follow onto choice B, whatever works; is your answer. (:

Answer 4

ill try. thanks :)

Answer 5

we discussed this before

If it is a dilation about the origin then all values will be multiplied by the |SAME factor

you can see in the first one J(6,7) => J' (6,21) does NOT meet that at x is multiplied by 1 but y is multiplied by 3

have a look at all the answers and find one where the transform has a common factor for all points...

Answer 6

i got b

Answer 7

i multiplied everything by 3 and it turned out to be b.

Answer 8

@rileychampion365

Answer 9

as before -
if you understand the concept and are confident of your answer - go with it

Answer 10

i got it right again! :)

Answer 11

well done - that's a habit worth acquiring :-)

Answer 12

do i still do the same if the corrdinates are negative?

Answer 13

yes (remember to keep the negative sign after you multiply

Answer 14

alright thanks!