Question

Can someone check my answer? Algebra II

Answer 1

\[2x+5/x^2-3x-10 \left( + \right) x+1/x+2\]

Answer 2

I got the answer ...\[x(x-2)/(x-5)(x+2)\]

Answer 3

@Hero

Answer 4

@Michele_Laino @nincompoop

Answer 5

@phi

Answer 6

@texaschic101

Answer 7

is this
\[ \frac{2x+5}{x^2-3x-10} + \frac{ x+1}{x+2} \]?

Answer 8

yes @phi

Answer 9

first factor the bottom of the first fraction (to get a better idea of what is going on)
\[ \frac{2x+5}{x^2-3x-10} + \frac{ x+1}{x+2} \\
\frac{2x+5}{(x+2)(x-5)} + \frac{ x+1}{x+2}
\]

Answer 10

That is what I did

Answer 11

to get a common denominator, multiply the second fraction by (x-5) (top and bottom)
\[ \frac{2x+5}{(x+2)(x-5)} + \frac{ (x+1)}{(x+2)} \frac{(x-5)}{(x-5)} \]

now we can add the tops. First, multiply out the top of the second fraction:
\[ \frac{2x+5}{(x+2)(x-5)} + \frac{ x^2-4x-5} {(x+2)(x-5)}\]

Answer 12

now add the tops and put the sum over the common denominator
\[\frac{ x^2-2x} {(x+2)(x-5)}\]
it looks like we can factor out an x
\[ \frac{ x(x-2)} {(x+2)(x-5)}\]

yes, it looks like the same thing as what you posted.

Answer 13

awesome! thanks for helping me out so quickly! @phi